2. Arithmetic Sequence is a sequence of
numbers such that the difference between
the consecutive terms is constant.
For instance, the sequence 5, 7, 9, 11, 13,
15 … is an arithmetic progression with
common difference of 2. &
2,6,18,54(next term to the term is to
be obtained by multiplying by 3.
Arithmetic Sequence
3.
4. Arithmetic Progression
If various terms of a sequence are formed by adding a
fixed number to the previous term or the difference
between two successive terms is a fixed number, then the
sequence is called AP.
e.g.1) 2, 4, 6, 8, ……… the sequence of even numbers is
an example of AP
2) 5, 10, 15, 20, 25….. In this each term is obtained by
adding 5 to the preceding term except first term.
5. If the initial term of an arithmetic progression is a1
and the common difference of successive members
is d, then the nth term of the sequence (an) is given
by:
and in general
6. • A finite portion of an arithmetic progression is called a finite
arithmetic progressionand sometimes just called an arithmetic
progression. The sum of a finite arithmetic progression is called
an Arithmetic series.
• The behavior of the arithmetic progressiondepends onthe
commondifference d. If the common difference is:
Positive, the members(terms) will grow towards positive infinity.
Negative, the members(terms)will grow towards negative
infinity.
7. Common Difference
If we take first term of an AP as a and Common Difference as d. Then--
nth term of that AP will be An = a + (n-1)d.
For instance--- 3, 7, 11, 15, 19 … d =4 a =3
Notice in this sequence that if we find the difference between any term
and the term before it we always get 4.
4 is then called the common difference and is denoted with the letter
d.
To get to the next term in the sequence we would add 4 so a recursive
formula for this sequence is:
The first term in the sequence would be a1 which is sometimes just
written as a.
41 nn aa
8. Example
Let a=2, d=2, n=12,find An
An=a+(n-1)d
=2+(12-1)2
=2+(11)2
=2+22
Therefore, An=24
Hence solved.
9. The difference between two terms of
an AP
The difference between two terms of
an AP can be formulated as below:-
nth term – kth term
= t(n) – t(k)
= {a + (n-1)d} – { a + (k-1) d }
= a + nd – d – a – kd + d = nd – kd
Hence,
t(n) – t(k) = (n – k) d
10. General Formulas of AP
• The general forms of an AP is a,(a+d), (a+2d),. .. , a +
( m - 1)d.
i. Nth term of the AP is Tn =a+(n-1)d.
ii. Nth term form the end ={l-(n-1)d}, where l is the
last term of the word.
iii. Sum of 1st n term of an AP is Sn=N/2{2a=(n-1)d}.
iv. Also Sn=n/2 (a+1)
v. Tn =(sn-Sn-1)
11. The sum of n terms, we find as,
Sum = n X [(first term + last term) / 2]
Now last term will be = a + (n-1) d
Therefore,
Sum(Sn) =n X [{a + a + (n-1) d } /2 ]
= n/2 [ 2a + (n+1)d]
12. • Solution.
1) First term is a = 100 , an = 500
2) Common difference is d = 105 -
100 = 5
3) nth term is an = a + (n-1)d
4) 500 = 100 + (n-1)5
5) 500 - 100 = 5(n – 1)
6) 400 = 5(n – 1)
7) 5(n – 1) = 400
8) 5(n – 1) = 400
9) n – 1 = 400/5
10) n - 1 = 80
11) n = 80 + 1
12) n = 81
Hence the no. of terms are 81.