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The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium . You can leave out water itself. Write the chemical formulas of the species that will act as acids in the \'acids\' row, the formulas of the species that will act as bases in the \'bases\' row, and the formulas of the species that will act as neither acids nor bases in the \'other\' row. The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the \'acids\' row, the formulas of the species that will act as bases in the \'bases\' row, and the formulas of the species that will act as neither acids nor bases in the \'other row. You will find it useful to keep in mind that HCH3CO2 is a weak acid acids: 0.7 mol of KOH is added to 1,0 L of a 0.7 MHCH,CO, solution IL, bases : other: 0.26 mol of NaOH is added toacids: 1.0 L of a solution that is 1.2 Min both HCH CO and CO2 and bases: D NaCH,Cop other: Solution 1) HCH3CO2 + KOH ----> KCH3CO2 + H2O KCH3CO2 IS BASIC. answer: bases, CH3CO2- acts as base. 2)Â Â HCH3CO2 <----> CH3CO2- + H+ NaCH3CO2 ----> CH3CO2- + Na+ after addition of base(OH-),dissociation of weakacid(HCH3CO2) increases.so that, it gives formation of CH3CO2-. which is basic. answer: bases, CH3CO2- .

The preparations of two aqueous solutions are described in the table below. For each solution,
write the chemical formulas of the major species present at equilibrium . You can leave out
water itself.
Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas
of the species that will act as bases in the 'bases' row, and the formulas of the species that will
act as neither acids nor bases in the 'other' row.
The preparations of two aqueous solutions are described in the table below. For each solution,
write the chemical formulas of the major species present at equilibrium. You can leave out water
itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the
formulas of the species that will act as bases in the 'bases' row, and the formulas of the species
that will act as neither acids nor bases in the 'other row. You will find it useful to keep in mind
that HCH3CO2 is a weak acid acids: 0.7 mol of KOH is added to 1,0 L of a 0.7 MHCH,CO,
solution IL, bases : other: 0.26 mol of NaOH is added toacids: 1.0 L of a solution that is 1.2 Min
both HCH CO and CO2 and bases: D NaCH,Cop other:
Solution
1) HCH3CO2 + KOH ----> KCH3CO2 + H2O
KCH3CO2 IS BASIC.
answer: bases, CH3CO2- acts as base.
2)Â Â HCH3CO2 <----> CH3CO2- + H+
NaCH3CO2 ----> CH3CO2- + Na+
after addition of base(OH-),dissociation of weakacid(HCH3CO2) increases.so that, it gives
formation of CH3CO2-. which is basic.
answer: bases, CH3CO2-

The preparations of two aqueous solutions are described in the table b.docx

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The primary difference between seasonality and cycles is? the duration of the repeating patterns the magnitude of the variation the ability to attribute the pattern to a cause the direction of the movement there are only 4 seasons but 30 cycles Solution answer is the duration of the repeating patterns explaination: Cycles are wavelike variation of more than one year\'s duration (long term). There are often related to a variety of economic, political, and even agricultural conditions. Seasonality refers to short-term, fairly variations generally related to factors such as the calendar or time of day. For example, restaurants, supermarkets, and theaters experience weekly and even daily \"seasonal\" variations. In one word, cycles are up-and-down movements similar to seasonal variation but of long duration-say, two to six years between peaks. .

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The nucleus of a 15 a distance of 5.4 x 10-11 m. What is the ratio of the density of the hydrogen nucleus to the density of the complete hydrogen atom? Section 30.1 10 30.P energy as a ground-state For a doubly ionized lithium atom Li2+ (z - 3), what is the principal quantum number of the state in which the electron has the same total Section 30.3 CJ10 36 P010 Solution 2) First find density of proton mass of proton = 1.67e-27 V = 4/3*pi*r 3 = 4/3*pi*(1.7e-15) 3 = 2.0579e-44 m 3 density = mass / volume = 1.67e-27 / 2.0579e-44 density = 8.115e16 kg/m 3 Mass of hydrogen atom = 1.67e-27 V = 4/2*pi*(5.4e-11) 3 = 6.596e-31 m 3 density = 1.67e-27 / 6.596e-31 density = 2531.9 kg/m3 Ratio =Â Â 8.115e16 / 2531.9 Ratio = 3.205e13 3) n 2 (Li) = (n 2 / Z 2 ) Hydrogen * Z 2 (Li) for ground state, n and z = 1 for hydrogen n 2 = 1*3 2 = 9 n (Li) = 3 .

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Please make comments of the following discussion in 150-200 words-If y.docx

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1. The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium . You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other row. You will find it useful to keep in mind that HCH3CO2 is a weak acid acids: 0.7 mol of KOH is added to 1,0 L of a 0.7 MHCH,CO, solution IL, bases : other: 0.26 mol of NaOH is added toacids: 1.0 L of a solution that is 1.2 Min both HCH CO and CO2 and bases: D NaCH,Cop other: Solution 1) HCH3CO2 + KOH ----> KCH3CO2 + H2O KCH3CO2 IS BASIC. answer: bases, CH3CO2- acts as base. 2)Â Â HCH3CO2 <----> CH3CO2- + H+ NaCH3CO2 ----> CH3CO2- + Na+ after addition of base(OH-),dissociation of weakacid(HCH3CO2) increases.so that, it gives formation of CH3CO2-. which is basic. answer: bases, CH3CO2-