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finish c++ code based on green line requirement
/ Given two linked lists, return a NEW linked-list where each element is the sum of the
corresponding elements of the input * If a linked list has a longer length than the other, treat the
corresponding NULL element as a node with value 0 Example: List 1:12312 List 2:456 / Node*
recursivel of the linked list 57912 ?

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finish c++ code based on green line requirement Given two .pdf

  • 1. finish c++ code based on green line requirement / Given two linked lists, return a NEW linked-list where each element is the sum of the corresponding elements of the input * If a linked list has a longer length than the other, treat the corresponding NULL element as a node with value 0 Example: List 1:12312 List 2:456 / Node* recursivel of the linked list 57912 ?