point charges of .29 µC and .82 µC are place .65 m apart. what is the magnitude of the electric field, in newtons per coulomb, halfway between them? Solution Electric field due to a point charge is given by: E = k|q|/r 2 So, E = kq1/r 2 - kq2/r 2 = (9*10^9)/(0.65/2)^2 * [0.82 - 0.29]*10^-6 = 4.52 x 10 4 N/C .