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# In the overhead view of the figure- a 430 g ball with a speed v of 9-0.docx

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# In the overhead view of the figure- a 430 g ball with a speed v of 9-0.docx

In the overhead view of the figure, a 430 g ball with a speed v of 9.0 m/s stikes a wall at an angle8 of 25 and then rebounds with the same speed and angle. It is in contact with the wall for 10 ms. In unit-vector notation, what are (a) the impuise on the ball from the wall and (b) the average force on the wall from the bal? oblem (a) Namber l Units (b) Number Units OType here to search ? Backspace Shift Alt AltE Ctri
Solution
We know
Impulse=change in momentum
Initial momentum=0.43*(vcos(theta)i-vsin(theta)j)
Final momentum=0.43*(vcos(theta)i+vsin(theta)j)
Change in momentum=0.43*2*v*sin(theta)=-3.27j
Impulse=-3.27j
(b) force=impulse/time=327.1 N
.

In the overhead view of the figure, a 430 g ball with a speed v of 9.0 m/s stikes a wall at an angle8 of 25 and then rebounds with the same speed and angle. It is in contact with the wall for 10 ms. In unit-vector notation, what are (a) the impuise on the ball from the wall and (b) the average force on the wall from the bal? oblem (a) Namber l Units (b) Number Units OType here to search ? Backspace Shift Alt AltE Ctri
Solution
We know
Impulse=change in momentum
Initial momentum=0.43*(vcos(theta)i-vsin(theta)j)
Final momentum=0.43*(vcos(theta)i+vsin(theta)j)
Change in momentum=0.43*2*v*sin(theta)=-3.27j
Impulse=-3.27j
(b) force=impulse/time=327.1 N
.

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### In the overhead view of the figure- a 430 g ball with a speed v of 9-0.docx

1. 1. In the overhead view of the figure, a 430 g ball with a speed v of 9.0 m/s stikes a wall at an angle8 of 25 and then rebounds with the same speed and angle. It is in contact with the wall for 10 ms. In unit-vector notation, what are (a) the impuise on the ball from the wall and (b) the average force on the wall from the bal? oblem (a) Namber l Units (b) Number Units OType here to search ? Backspace Shift Alt AltE Ctri Solution We know Impulse=change in momentum Initial momentum=0.43*(vcos(theta)i-vsin(theta)j) Final momentum=0.43*(vcos(theta)i+vsin(theta)j) Change in momentum=0.43*2*v*sin(theta)=-3.27j Impulse=-3.27j (b) force=impulse/time=327.1 N