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Recently, Major League Baseball teams have become concerned about the length of games.
During the 2009 season, games averaged 2 hours and 52 minutes (172) minutes) to complete.
Assume the length of games follows the normal distribution with a standard deviation of 16
minutes. 1.What is the probability that a randomly selected game will be completed in
Solution
a. P(X<200) = P((X-mean)/s <(200-172)/16) =P(Z<1.75) =0.9599 (check standard
normal table) --------------------------------------------------------- b. P(X>150) = P(Z>(150-172)/16)
=P(Z>-1.38) =0.9162 (check standard normal table) -----------------------------------------------------
- c. P(X P(Z<(c-172)/16)=0.9 --> (c-172)/16 =1.28 (check standard normal table) --> c
=172+1.28*16=192.48

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Recently, Major League Baseball teams have become concerned about th.pdf

  • 1. Recently, Major League Baseball teams have become concerned about the length of games. During the 2009 season, games averaged 2 hours and 52 minutes (172) minutes) to complete. Assume the length of games follows the normal distribution with a standard deviation of 16 minutes. 1.What is the probability that a randomly selected game will be completed in Solution a. P(X<200) = P((X-mean)/s <(200-172)/16) =P(Z<1.75) =0.9599 (check standard normal table) --------------------------------------------------------- b. P(X>150) = P(Z>(150-172)/16) =P(Z>-1.38) =0.9162 (check standard normal table) ----------------------------------------------------- - c. P(X P(Z<(c-172)/16)=0.9 --> (c-172)/16 =1.28 (check standard normal table) --> c =172+1.28*16=192.48