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Devoirsetexamenssur:www.kiteb.net
Devoirsetexamenssur:www.kiteb.net
Devoirsetexamenssur:www.kiteb.net
Devoirsetexamenssur:www.kiteb.net
Corrigés Bac pratique Informatique
Section Sciences de l'informatique
23 mai 2013(8h)
Jeudi 23 mai 2013 à 8h
program aires_23_05_2013_8h;
uses wincrt;
const
a=0;
b=3;
type
tenreg= record
rect:real;
trap:real;
nb:integer;
end;
tf=file of tenreg;
var
f:tf;
v:tenreg;
 eps:real;
   rep:integer;
{**************************************************************}
function fct (x:real):real;
begin
    fct:=sqr(x);
end;  
 {*************************************************************}
  procedure  epsilon (var eps:real);
  begin
      repeat
           write(' taper une valeur pour epsilon:');readln(eps);
      until (eps>=0.0001) and (eps<=0.1);
  end;
  
  {*************************************************************}
 function rectangle ( n:integer):real;
 var
   x, h,S:real;
    i:integer;
 begin
       S:=0;
       h:=(b­a)/n;
       x:=(a+h/2);
       for i:=1 to n do
       begin
          S:=S+fct(x);
1/9
Correction proposée par
Mr Mejdi Bechikh & Mme Hajer NEFZAOUI
Devoirsetexamenssur:www.kiteb.net
          x:=x+h;
       end;
       rectangle:=s*h;
 end;
    {*************************************************************}
 function trapeze ( n:integer):real;
 var
   x, h,S:real;
    i:integer;
 begin
       
       h:=(b+a)/n;
       s:=(fct(a)+fct(a+h))/2;
       x:=a;
       for i:=1 to n­1 do
       begin
         x:=x+h;
          S:=S+(fct(x)+fct(x+h))/2;
     
       end;
       trapeze:=s*h;
 end;
 {******************************************************}
 procedure trait (var f:tf; eps:real; var rep:integer);
 var
     n:integer;
     v:tenreg;
     Dif1,dif2,A1,A2:real;
 begin
     reset(f);
           n:=1;
     repeat
     n:=n+1;
     A1:=rectangle(n);
     A2:=trapeze(n);
     v.nb:=n;
     V.rect:=A1;
     v.trap:=A2;
     write(f,v);
     dif1:=abs(rectangle(n)­rectangle(n­1));
     dif2:=abs(trapeze(n)­trapeze(n­1));
     writeln('n=',n, A1:9:5, A2:9:5);readln;
     until (dif1<=eps)or(dif2<=eps);
    {if (dif1<dif2) then rep:=1
    else  if (dif2<dif1) then rep:=2
    else rep:=3;}
     if (dif1<eps) then rep:=1;
     if (dif2<eps) then rep:=2;
    
    writeln('la methode est ',rep);
     close(f);
2/9
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 end;
  {******************************************************}
 procedure afficher (var f:tf; rep:integer);
 var
 v:tenreg;  mes:string;
 begin
 writeln('***N****','*Rectangle*','*trapeze*');
 reset(f);
 while not(eof(f))do
 begin
     read(f,v);
     writeln(v.nb,v.rect:9:5,v.trap:9:5);
 end;
 if rep=1 then mes:='Med des rectangles'
 else if rep=2 then mes:='Med des trapèzes'
 else mes:='Exéquo';
    writeln('la methode qui converge la première est :',mes);
 end;
 BEGIN
 assign(f,'c:calcul.dat');
 rewrite(f);
 repeat
 epsilon(eps);
 writeln(rectangle(5));
 trait(f,eps,rep);
 afficher(f,rep);
  until keypressed;
 END.
3/9
Devoirsetexamenssur:www.kiteb.net
Corrigés Bac pratique Informatique
Section Sciences de l'informatique
23 mai 2013(10h)
Jeudi 23 mai 2013 à 10h
program seance2_23_05_2013_10h;
uses wincrt;
var
f,fc:text;
n:integer;
procedure saisie (var n: integer);
begin
    repeat
          write(' taper n:'); readln(n);
    until (n<=50);
end;
function verif (ch:string):boolean;
var
i:integer;
begin
      i:=0;
repeat
       i:=i+1;
until (not(upcase(ch[i]) in ['A'..'Z',' ']))or(i=length(ch));
verif:=(upcase(ch[i]) in ['A'..'Z',' '])and(ch[1]<>' 
')and(ch[length(ch)]<>' ')and(pos('  ',ch)=0);
end;
procedure saisie_ph( var ph:string);
begin
 repeat
      write('Taper une phrase :');readln(ph);
 until (verif(ph)); 
end;
function crypter (mot:string; p:integer):string;
 var
 motc:string;
 c:char;
 i:integer;
 begin
    motc:='';
    for i:=1 to length(mot) do
    begin
         if (mot[i] in ['A'..'Z']) then
4/9
Correction proposée par
Mr Mejdi Bechikh & Mme Hajer NEFZAOUI
Devoirsetexamenssur:www.kiteb.net
         begin
         if   chr(ord(mot[i])+p)<'Z' then
                                      c:=chr(ord(mot[i])+p)
         else
              c:=chr( (ord(mot[i])+p­90) mod 26 +64);
         end  ;
         
         if (mot[i] in ['a'..'z']) then
         begin
         if   chr(ord(mot[i])+p)<'z' then
                                      c:=chr(ord(mot[i])+p)
         else
              c:=chr( (ord(mot[i])+p­122) mod 26 +97);
         end;
        motc:=motc+c;
    end;
    
     crypter:=motc;
      end;
      function crypter_ph( ph:string):string;
      var
      ch1,phc:string;
      i,p:integer;
      
        begin
            phc:='';
            p:=0;
         
            ph:=ph+' ';
            while(ph<>'')do
            begin
              p:=p+1;
              ch1:=crypter(copy(ph,1,pos(' ',ph)­1),p);
              phc:=phc+ch1+' ';
              delete(ph,1,pos(' ',ph));
            end;
              delete(phc,length(ph),1);
            crypter_ph:=phc;
        end;
     procedure traitement (var f,fc:text; n:integer);              
     var
     i:integer;
     phc,ph:string;
     begin
               append(f); append(fc);
               for i:=1 to n do
               begin
                 saisie_ph(ph);
                 phc:=crypter_ph(ph);
5/9
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                 write(f,ph);
                 write(fc,phc);
                 writeln(ph);
                 writeln(phc);
               end;
      close(f);close(fc);
     end;
      
BEGIN
assign(f,'c:phrases.txt'); rewrite(f);
assign(fc,'c:ph_crypt.txt'); rewrite(fc);
saisie(n);
traitement(f,fc,n);
       
END.
6/9
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Corrigés Bac pratique Informatique
Section Sciences de l'informatique
23 mai 2013(14h)
Jeudi 23 mai 2013 à 14h
program seance3_23_05_2013_14h;
uses wincrt;
type
mat= array[1..24,1..24]of integer;
 tenreg=record
 nl,ICD,ICF:integer;
 end;
tab= array [1..24] of tenreg;
 VAR
 L,C ,k:integer;
 M:mat;
 T:tab;
 F:text;
 procedure remplir (var L,c:integer ; var M:mat);
 var
 i,j:integer;
 begin
     repeat
           write(' taper L:');readln(l);
             write(' taper c:');readln(c);
     until (l in [3..24]) and (c in [3..24]);
     for i:=1 to  l do
     begin
         for j:=1 to c do
         Repeat
              write('M[',i,',',j,']='); readln(M[i,j]);
         Until (m[i,j]<>0);
     end;
 end;
 procedure Somme (m:mat; lig,col,c:integer; var Fin:integer);
 var
     i,j,s:integer;
 begin
       Fin:=0; S:=0; i:=lig; j:=col;
       repeat
             s:=s+m[lig,j];
             j:=j+1;
       until (S=0) or (j >c);
       if (s=0) then fin:=j­1;
    end;
7/9
Correction proposée par
Mr Mejdi Bechikh & Mme Hajer NEFZAOUI
Devoirsetexamenssur:www.kiteb.net
 procedure traitement (var t:tab; m:mat; l,c:integer; var k:integer );
    var
       s,f,i,j:integer;
     begin
         k:=0;
         for i:=1 to l do
         begin
         for j:=1 to c do
         begin
              somme(m,i,j,c,f);
              if (f<>0) then
                        begin
                        k:=k+1;
                            T[k].Nl:=i;
                            T[k].ICD:=j;
                            T[k].ICF:=f;
                            { writeln(i,'#',j,'#',f);}
                        end;
          end;
         end;
              end;
         function maximum ( t:tab; k:integer ):integer;
              var
               i,max:integer;
               begin
                   max:=(T[1].ICF­T[1].ICD+1);
                   for i:=2 to k do
                   begin
                       if (T[i].ICF­T[i].ICD+1) > max then
                                           max:=T[i].ICF­T[i].ICD+1;
                   end;
                 maximum:=max;
               end;
         procedure Stockage (var F:text ; t:tab ; k:integer);
         var
             max,i:integer;
            chm,ligne1, ch,ch1,ch2,ch3:string;
         begin
         append(f);
         max:=maximum(t,k);
         STR(max,chm); 
    ligne1:=' Le nombre d''elements de la plus longue séquence ='+chm;
         writeln(f,ligne1);
8/9
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         writeln(ligne1);
                for i:=1 to k do
                begin
                   if (T[i].ICF­T[i].ICD+1) = max then
                                            begin
                                                Str(T[i].nl,ch1);
                                                Str(T[i].ICD,ch2);
                                                Str(T[i].ICF,ch3);
                                                
ch:=ch1+'#'+ch2+'#'+ch3;
                                                writeln(f,ch);
                                                writeln(ch);
                                            end;
                end;
           Close(f);
         end;
 
 BEGIN
 assign(f,'C:long_Seq.txt');
 rewrite(f);
     remplir (l,c,m);
     traitement (t,m,l,c,k);
     stockage (f,t,k);
 END.
9/9
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Sujet bac info 2013 g1, g2 et g3 avec correction