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Exercice 16
    (a)

                        0, 777 · · · = 0, 7 + 0, 07 + 0, 007 + · · ·
                                        7      7       7
                                     =     +       +       + ···
                                       10 100 1000
          Il s’agit d’une progression géométrique illimitée dont : a1 = 7/10
          et r = 1/10
          Donc :

                                           a1
                                   S∞ =
                                         1−r
                                            7/10
                                       =
                                         1 − 1/10
                                         7/10
                                       =       = 7/9
                                         9/10
Exercice 16 (suite..)
    (b)
                                          34   34      34
                       0, 3434 · · · =       +    2
                                                    +      + ···
                                         100 100      1003
          Il s’agit d’une progression géométrique illimitée dont   a1 =    34
                                                                          100
          et r = 100 .
                     1

          Donc :
                                        a1
                                S∞ =
                                      1−r
                                        34/100
                                    =
                                      1 − 1/100
                                      34/100
                                    =         = 34/99
                                      99/100
Exercice 16 (suite..)
    (c)

                      4, 2222 · · · = 4 + 0, 2222 · · ·
                                           2      2       2
                                    =4+       +         +   + ···
                                          10 100 1000
          Il s’agit d’une progression geómétrique illimitée dont    a1 =    2
                                                                           10
          et r = 10  1

          Alors :
                                             a1
                                   S∞ =
                                           1−r
                                              2/10
                                         =
                                           1 − 1/10
                                           2/10
                                         =       = 2/9
                                           9/10

          Donc :   4, 2222 · · · = 4 +   2
                                         9
                                             =   38
                                                  9

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Ch15 16

  • 1. Exercice 16 (a) 0, 777 · · · = 0, 7 + 0, 07 + 0, 007 + · · · 7 7 7 = + + + ··· 10 100 1000 Il s’agit d’une progression géométrique illimitée dont : a1 = 7/10 et r = 1/10 Donc : a1 S∞ = 1−r 7/10 = 1 − 1/10 7/10 = = 7/9 9/10
  • 2. Exercice 16 (suite..) (b) 34 34 34 0, 3434 · · · = + 2 + + ··· 100 100 1003 Il s’agit d’une progression géométrique illimitée dont a1 = 34 100 et r = 100 . 1 Donc : a1 S∞ = 1−r 34/100 = 1 − 1/100 34/100 = = 34/99 99/100
  • 3. Exercice 16 (suite..) (c) 4, 2222 · · · = 4 + 0, 2222 · · · 2 2 2 =4+ + + + ··· 10 100 1000 Il s’agit d’une progression geómétrique illimitée dont a1 = 2 10 et r = 10 1 Alors : a1 S∞ = 1−r 2/10 = 1 − 1/10 2/10 = = 2/9 9/10 Donc : 4, 2222 · · · = 4 + 2 9 = 38 9